Resources
Resources are types that can only exist in one location at a time and must be used exactly once.
Resources must be created (instantiated) by using the create
keyword.
At the end of a function which has resources (variables, constants, parameters) in scope, the resources must be either moved or destroyed.
They are moved when used as an initial value for a constant or variable, when assigned to a different variable, when passed as an argument to a function, and when returned from a function.
Resources can be explicitly destroyed using the destroy
keyword.
Accessing a field or calling a function of a resource does not move or destroy it.
When the resource is moved, the constant or variable that referred to the resource before the move becomes invalid. An invalid resource cannot be used again.
To make the usage and behaviour of resource types explicit,
the prefix @
must be used in type annotations
of variable or constant declarations, parameters, and return types.
The Move Operator (<-
)​
To make moves of resources explicit, the move operator <-
must be used
when the resource is the initial value of a constant or variable,
when it is moved to a different variable,
when it is moved to a function as an argument,
and when it is returned from a function.
_43// Declare a resource named `SomeResource`, with a variable integer field._43//_43pub resource SomeResource {_43 pub var value: Int_43_43 init(value: Int) {_43 self.value = value_43 }_43}_43_43// Declare a constant with value of resource type `SomeResource`._43//_43let a: @SomeResource <- create SomeResource(value: 0)_43_43// *Move* the resource value to a new constant._43//_43let b <- a_43_43// Invalid: Cannot use constant `a` anymore as the resource that it referred to_43// was moved to constant `b`._43//_43a.value_43_43// Constant `b` owns the resource._43//_43b.value // equals 0_43_43// Declare a function which accepts a resource._43//_43// The parameter has a resource type, so the type annotation must be prefixed with `@`._43//_43pub fun use(resource: @SomeResource) {_43 // ..._43}_43_43// Call function `use` and move the resource into it._43//_43use(resource: <-b)_43_43// Invalid: Cannot use constant `b` anymore as the resource_43// it referred to was moved into function `use`._43//_43b.value
A resource object cannot go out of scope and be dynamically lost. The program must either explicitly destroy it or move it to another context.
_10{_10 // Declare another, unrelated value of resource type `SomeResource`._10 //_10 let c <- create SomeResource(value: 10)_10_10 // Invalid: `c` is not used before the end of the scope, but must be._10 // It cannot be lost._10}
_12// Declare another, unrelated value of resource type `SomeResource`._12//_12let d <- create SomeResource(value: 20)_12_12// Destroy the resource referred to by constant `d`._12//_12destroy d_12_12// Invalid: Cannot use constant `d` anymore as the resource_12// it referred to was destroyed._12//_12d.value
To make it explicit that the type is a resource type
and must follow the rules associated with resources,
it must be prefixed with @
in all type annotations,
e.g. for variable declarations, parameters, or return types.
_23// Declare a constant with an explicit type annotation._23//_23// The constant has a resource type, so the type annotation must be prefixed with `@`._23//_23let someResource: @SomeResource <- create SomeResource(value: 5)_23_23// Declare a function which consumes a resource and destroys it._23//_23// The parameter has a resource type, so the type annotation must be prefixed with `@`._23//_23pub fun use(resource: @SomeResource) {_23 destroy resource_23}_23_23// Declare a function which returns a resource._23//_23// The return type is a resource type, so the type annotation must be prefixed with `@`._23// The return statement must also use the `<-` operator to make it explicit the resource is moved._23//_23pub fun get(): @SomeResource {_23 let newResource <- create SomeResource()_23 return <-newResource_23}
Resources must be used exactly once.
_10// Declare a function which consumes a resource but does not use it._10// This function is invalid, because it would cause a loss of the resource._10//_10pub fun forgetToUse(resource: @SomeResource) {_10 // Invalid: The resource parameter `resource` is not used, but must be._10}
_15// Declare a constant named `res` which has the resource type `SomeResource`._15let res <- create SomeResource()_15_15// Call the function `use` and move the resource `res` into it._15use(resource: <-res)_15_15// Invalid: The resource constant `res` cannot be used again,_15// as it was moved in the previous function call._15//_15use(resource: <-res)_15_15// Invalid: The resource constant `res` cannot be used again,_15// as it was moved in the previous function call._15//_15res.value
_12// Declare a function which has a resource parameter._12// This function is invalid, because it does not always use the resource parameter,_12// which would cause a loss of the resource._12//_12pub fun sometimesDestroy(resource: @SomeResource, destroyResource: Bool) {_12 if destroyResource {_12 destroy resource_12 }_12 // Invalid: The resource parameter `resource` is not always used, but must be._12 // The destroy statement is not always executed, so at the end of this function_12 // it might have been destroyed or not._12}
_13// Declare a function which has a resource parameter._13// This function is valid, as it always uses the resource parameter,_13// and does not cause a loss of the resource._13//_13pub fun alwaysUse(resource: @SomeResource, destroyResource: Bool) {_13 if destroyResource {_13 destroy resource_13 } else {_13 use(resource: <-resource)_13 }_13 // At the end of the function the resource parameter was definitely used:_13 // It was either destroyed or moved in the call of function `use`._13}
_19// Declare a function which has a resource parameter._19// This function is invalid, because it does not always use the resource parameter,_19// which would cause a loss of the resource._19//_19pub fun returnBeforeDestroy(move: Bool) {_19 let res <- create SomeResource(value: 1)_19 if move {_19 use(resource: <-res)_19 return_19 } else {_19 // Invalid: When this function returns here, the resource variable_19 // `res` was not used, but must be._19 return_19 }_19 // Invalid: the resource variable `res` was potentially moved in the_19 // previous if-statement, and both branches definitely return,_19 // so this statement is unreachable._19 destroy res_19}
Resource Variables​
Resource variables cannot be assigned to, as that would lead to the loss of the variable's current resource value.
Instead, use a swap statement (<->
) or shift statement (<- target <-
)
to replace the resource variable with another resource.
_23pub resource R {}_23_23var x <- create R()_23var y <- create R()_23_23// Invalid: Cannot assign to resource variable `x`,_23// as its current resource would be lost_23//_23x <- y_23_23// Instead, use a swap statement._23//_23var replacement <- create R()_23x <-> replacement_23// `x` is the new resource._23// `replacement` is the old resource._23_23// Or use the shift statement (`<- target <-`)_23// This statement moves the resource out of `x` and into `oldX`,_23// and at the same time assigns `x` with the new value on the right-hand side._23let oldX <- x <- create R()_23// oldX still needs to be explicitly handled after this statement_23destroy oldX
Resource Destructors​
Resource may have a destructor, which is executed when the resource is destroyed.
Destructors have no parameters and no return value and are declared using the destroy
name.
A resource may have only one destructor.
_15var destructorCalled = false_15_15pub resource Resource {_15_15 // Declare a destructor for the resource, which is executed_15 // when the resource is destroyed._15 //_15 destroy() {_15 destructorCalled = true_15 }_15}_15_15let res <- create Resource()_15destroy res_15// `destructorCalled` is `true`
Nested Resources​
Fields in composite types behave differently when they have a resource type.
If a resource type has fields that have a resource type, it must declare a destructor, which must invalidate all resource fields, i.e. move or destroy them.
_28pub resource Child {_28 let name: String_28_28 init(name: String)_28 self.name = name_28 }_28}_28_28// Declare a resource with a resource field named `child`._28// The resource *must* declare a destructor_28// and the destructor *must* invalidate the resource field._28//_28pub resource Parent {_28 let name: String_28 var child: @Child_28_28 init(name: String, child: @Child) {_28 self.name = name_28 self.child <- child_28 }_28_28 // Declare a destructor which invalidates the resource field_28 // `child` by destroying it._28 //_28 destroy() {_28 destroy self.child_28 }_28}
Accessing a field or calling function on a resource field is valid, however moving a resource out of a variable resource field is not allowed. Instead, use a swap statement to replace the resource with another resource.
_15let child <- create Child(name: "Child 1")_15let parent <- create Parent(name: "Parent", child: <-child)_15_15child.name // is "Child 1"_15parent.child.name // is "Child 1"_15_15// Invalid: Cannot move resource out of variable resource field._15let childAgain <- parent.child_15_15// Instead, use a swap statement._15//_15var otherChild <- create Child(name: "Child 2")_15parent.child <-> otherChild_15// `parent.child` is the second child, Child 2._15// `otherChild` is the first child, Child 1.
Resources in Closures​
Resources can not be captured in closures, as that could potentially result in duplications.
_13resource R {}_13_13// Invalid: Declare a function which returns a closure which refers to_13// the resource parameter `resource`. Each call to the returned function_13// would return the resource, which should not be possible._13//_13fun makeCloner(resource: @R): ((): @R) {_13 return fun (): @R {_13 return <-resource_13 }_13}_13_13let test = makeCloner(resource: <-create R())
Resources in Arrays and Dictionaries​
Arrays and dictionaries behave differently when they contain resources: It is not allowed to index into an array to read an element at a certain index or assign to it, or index into a dictionary to read a value for a certain key or set a value for the key.
Instead, use a swap statement (<->
) or shift statement (<- target <-
)
to replace the accessed resource with another resource.
_34resource R {}_34_34// Declare a constant for an array of resources._34// Create two resources and move them into the array._34// `resources` has type `@[R]`_34//_34let resources <- [_34 <-create R(),_34 <-create R()_34]_34_34// Invalid: Reading an element from a resource array is not allowed._34//_34let firstResource <- resources[0]_34_34// Invalid: Setting an element in a resource array is not allowed,_34// as it would result in the loss of the current value._34//_34resources[0] <- create R()_34_34// Instead, when attempting to either read an element or update an element_34// in a resource array, use a swap statement with a variable to replace_34// the accessed element._34//_34var res <- create R()_34resources[0] <-> res_34// `resources[0]` now contains the new resource._34// `res` now contains the old resource._34_34// Use the shift statement to move the new resource into_34// the array at the same time that the old resource is being moved out_34let oldRes <- resources[0] <- create R()_34// The old object still needs to be handled_34destroy oldRes
The same applies to dictionaries.
_42// Declare a constant for a dictionary of resources._42// Create two resources and move them into the dictionary._42// `resources` has type `@{String: R}`_42//_42let resources <- {_42 "r1": <-create R(),_42 "r2": <-create R()_42}_42_42// Invalid: Reading an element from a resource dictionary is not allowed._42// It's not obvious that an access like this would have to remove_42// the key from the dictionary._42//_42let firstResource <- resources["r1"]_42_42// Instead, make the removal explicit by using the `remove` function._42let firstResource <- resources.remove(key: "r1")_42_42// Invalid: Setting an element in a resource dictionary is not allowed,_42// as it would result in the loss of the current value._42//_42resources["r1"] <- create R()_42_42// Instead, when attempting to either read an element or update an element_42// in a resource dictionary, use a swap statement with a variable to replace_42// the accessed element._42//_42// The result of a dictionary read is optional, as the given key might not_42// exist in the dictionary._42// The types on both sides of the swap operator must be the same,_42// so also declare the variable as an optional._42//_42var res: @R? <- create R()_42resources["r1"] <-> res_42// `resources["r1"]` now contains the new resource._42// `res` now contains the old resource._42_42// Use the shift statement to move the new resource into_42// the dictionary at the same time that the old resource is being moved out_42let oldRes <- resources["r2"] <- create R()_42// The old object still needs to be handled_42destroy oldRes
Resources cannot be moved into arrays and dictionaries multiple times, as that would cause a duplication.
_10let resource <- create R()_10_10// Invalid: The resource variable `resource` can only be moved into the array once._10//_10let resources <- [_10 <-resource,_10 <-resource_10]
_10let resource <- create R()_10_10// Invalid: The resource variable `resource` can only be moved into the dictionary once._10let resources <- {_10 "res1": <-resource,_10 "res2": <-resource_10}
Resource arrays and dictionaries can be destroyed.
_10let resources <- [_10 <-create R(),_10 <-create R()_10]_10destroy resources
_10let resources <- {_10 "r1": <-create R(),_10 "r2": <-create R()_10}_10destroy resources
The variable array functions like append
, insert
, and remove
behave like for non-resource arrays.
Note however, that the result of the remove
functions must be used.
_18let resources <- [<-create R()]_18// `resources.length` is `1`_18_18resources.append(<-create R())_18// `resources.length` is `2`_18_18let first <- resource.remove(at: 0)_18// `resources.length` is `1`_18destroy first_18_18resources.insert(at: 0, <-create R())_18// `resources.length` is `2`_18_18// Invalid: The statement ignores the result of the call to `remove`,_18// which would result in a loss._18resource.remove(at: 0)_18_18destroy resources
The variable array function contains
is not available, as it is impossible:
If the resource can be passed to the contains
function,
it is by definition not in the array.
The variable array function concat
is not available,
as it would result in the duplication of resources.
The dictionary functions like insert
and remove
behave like for non-resource dictionaries.
Note however, that the result of these functions must be used.
_18let resources <- {"r1": <-create R()}_18// `resources.length` is `1`_18_18let first <- resource.remove(key: "r1")_18// `resources.length` is `0`_18destroy first_18_18let old <- resources.insert(key: "r1", <-create R())_18// `old` is nil, as there was no value for the key "r1"_18// `resources.length` is `1`_18_18let old2 <- resources.insert(key: "r1", <-create R())_18// `old2` is the old value for the key "r1"_18// `resources.length` is `1`_18_18destroy old_18destroy old2_18destroy resources
Resource Identifier​
Resources have an implicit unique identifier associated with them,
implemented by a predeclared public field let uuid: UInt64
on each resource.
This identifier will be automatically set when the resource is created, before the resource's initializer is called (i.e. the identifier can be used in the initializer), and will be unique even after the resource is destroyed, i.e. no two resources will ever have the same identifier.
_22// Declare a resource without any fields._22resource R {}_22_22// Create two resources_22let r1 <- create R()_22let r2 <- create R()_22_22// Get each resource's unique identifier_22let id1 = r1.uuid_22let id2 = r2.uuid_22_22// Destroy the first resource_22destroy r1_22_22// Create a third resource_22let r3 <- create R()_22_22let id3 = r3.uuid_22_22id1 != id2 // true_22id2 != id3 // true_22id3 != id1 // true
The details of how the identifiers are generated is an implementation detail.
Do not rely on or assume any particular behaviour in Cadence programs.
Resource Owner​
Resources have the implicit field let owner: PublicAccount?
.
If the resource is currently stored in an account,
then the field contains the publicly accessible portion of the account.
Otherwise the field is nil
.
The field's value changes when the resource is moved from outside account storage into account storage, when it is moved from the storage of one account to the storage of another account, and when it is moved out of account storage.